Below is the syntax highlighted version of Maze.java
from §4.1 Undirected Graphs.
/************************************************************************* * Compilation: javac Maze.java * Execution: java Maze.java N * Dependecies: StdDraw.java * * Generates a perfect N-by-N maze using depth-first search with a stack. * * % java Maze 62 * * Note: this program generalizes nicely to finding a random tree * in a graph. * *************************************************************************/ public class Maze { private int N; // dimension of maze private boolean[][] north; // is there a wall to north of cell i, j private boolean[][] east; private boolean[][] south; private boolean[][] west; private boolean[][] visited; private double size; private boolean done = false; public Maze(int N) { this.N = N; StdDraw.setXscale(0, N+2); StdDraw.setYscale(0, N+2); init(); generate(); } private void init() { // initialize border cells as already visited visited = new boolean[N+2][N+2]; for (int x = 0; x < N+2; x++) visited[x][0] = visited[x][N+1] = true; for (int y = 0; y < N+2; y++) visited[0][y] = visited[N+1][y] = true; // initialze all wells as present north = new boolean[N+2][N+2]; east = new boolean[N+2][N+2]; south = new boolean[N+2][N+2]; west = new boolean[N+2][N+2]; for (int x = 0; x < N+2; x++) for (int y = 0; y < N+2; y++) north[x][y] = east[x][y] = south[x][y] = west[x][y] = true; } // generate the maze private void generate(int x, int y) { visited[x][y] = true; // while there is an univisited neighbor while (!visited[x][y+1] || !visited[x+1][y] || !visited[x][y-1] || !visited[x-1][y]) { // pick random neighbor (could use Knuth's trick instead) while (true) { double r = Math.random(); if (r < 0.25 && !visited[x][y+1]) { north[x][y] = south[x][y+1] = false; generate(x, y + 1); break; } else if (r >= 0.25 && r < 0.50 && !visited[x+1][y]) { east[x][y] = west[x+1][y] = false; generate(x+1, y); break; } else if (r >= 0.5 && r < 0.75 && !visited[x][y-1]) { south[x][y] = north[x][y-1] = false; generate(x, y-1); break; } else if (r >= 0.75 && r < 1.00 && !visited[x-1][y]) { west[x][y] = east[x-1][y] = false; generate(x-1, y); break; } } } } // generate the maze starting from lower left private void generate() { generate(1, 1); /* // delete some random walls for (int i = 0; i < N; i++) { int x = (int) (1 + Math.random() * (N-1)); int y = (int) (1 + Math.random() * (N-1)); north[x][y] = south[x][y+1] = false; } // add some random walls for (int i = 0; i < 10; i++) { int x = (int) (N / 2 + Math.random() * (N / 2)); int y = (int) (N / 2 + Math.random() * (N / 2)); east[x][y] = west[x+1][y] = true; } */ } // solve the maze using depth first search private void solve(int x, int y) { if (x == 0 || y == 0 || x == N+1 || y == N+1) return; if (done || visited[x][y]) return; visited[x][y] = true; StdDraw.setPenColor(StdDraw.BLUE); StdDraw.filledCircle(x + 0.5, y + 0.5, 0.25); StdDraw.show(30); // reached middle if (x == N/2 && y == N/2) done = true; if (!north[x][y]) solve(x, y + 1); if (!east[x][y]) solve(x + 1, y); if (!south[x][y]) solve(x, y - 1); if (!west[x][y]) solve(x - 1, y); if (done) return; StdDraw.setPenColor(StdDraw.GRAY); StdDraw.filledCircle(x + 0.5, y + 0.5, 0.25); StdDraw.show(30); } // solve the maze starting from the start state public void solve() { for (int x = 1; x <= N; x++) for (int y = 1; y <= N; y++) visited[x][y] = false; done = false; solve(1, 1); } // display the maze in turtle graphics public void draw() { StdDraw.setPenColor(StdDraw.RED); StdDraw.filledCircle(0.5*N + 0.5, 0.5*N + 0.5, 0.375); StdDraw.filledCircle(1.5, 1.5, 0.375); StdDraw.setPenColor(StdDraw.BLACK); for (int x = 1; x <= N; x++) { for (int y = 1; y <= N; y++) { if (south[x][y]) StdDraw.line(x, y, x + 1, y); if (north[x][y]) StdDraw.line(x, y + 1, x + 1, y + 1); if (west[x][y]) StdDraw.line(x, y, x, y + 1); if (east[x][y]) StdDraw.line(x + 1, y, x + 1, y + 1); } } StdDraw.show(1000); } // a test client public static void main(String[] args) { int N = Integer.parseInt(args[0]); Maze maze = new Maze(N); StdDraw.show(0); maze.draw(); maze.solve(); } }