Below is the syntax highlighted version of TwoSumFast.java
from §1.4 Analysis of Algorithms.
/************************************************************************* * Compilation: javac TwoSumFast.java * Execution: java TwoSumFast input.txt * * Dependencies: In.java Stopwatch.java * Data files: http://algs4.cs.princeton.edu/14analysis/1Kints.txt * http://algs4.cs.princeton.edu/14analysis/2Kints.txt * http://algs4.cs.princeton.edu/14analysis/4Kints.txt * http://algs4.cs.princeton.edu/14analysis/8Kints.txt * http://algs4.cs.princeton.edu/14analysis/16Kints.txt * http://algs4.cs.princeton.edu/14analysis/32Kints.txt * http://algs4.cs.princeton.edu/14analysis/1Mints.txt * * A program with N log N running time. Read in N integers * and counts the number of pairs that sum to exactly 0. * * Limitations * ----------- * - we ignore integer overflow * * * % java TwoSumFast 2Kints.txt * 2 * * % java TwoSumFast 1Kints.txt * 1 * * % java TwoSumFast 2Kints.txt * 2 * * % java TwoSumFast 4Kints.txt * 3 * * % java TwoSumFast 8Kints.txt * 19 * * % java TwoSumFast 16Kints.txt * 66 * * % java TwoSumFast 32Kints.txt * 273 * *************************************************************************/ import java.util.Arrays; public class TwoSumFast { // print distinct pairs (i, j) such that a[i] + a[j] = 0 public static void printAll(int[] a) { int N = a.length; Arrays.sort(a); for (int i = 0; i < N; i++) { int j = Arrays.binarySearch(a, -a[i]); if (j > i) StdOut.println(a[i] + " " + a[j]); } } // return number of distinct pairs (i, j) such that a[i] + a[j] = 0 public static int count(int[] a) { int N = a.length; Arrays.sort(a); int cnt = 0; for (int i = 0; i < N; i++) { int j = Arrays.binarySearch(a, -a[i]); if (j > i) cnt++; } return cnt; } public static void main(String[] args) { int[] a = In.readInts(args[0]); int cnt = count(a); StdOut.println(cnt); } }